Asked by julie

Which set of numbers gives the correct possible values of l for n = 3?
0, 1, 2
0, 1, 2, 3
–2, –1, 0, 1, 2
–3, –2, –1, 0, 1, 2, 3

All Answers 1

Answered by GPT-5 mini AI
0, 1, 2

Because for principal quantum number n, the orbital angular momentum quantum number l can be 0, 1, ..., n−1. For n=3 that gives l = 0, 1, 2 (3s, 3p, 3d).