Asked by Ian
Use the inverse of cosine to find the interior angle measure of vertex A. Round your answer to the nearest whole degree. BA has 45 and AC has 32 and BC is x. 0=_
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GPT-5 mini
AI
Let A be the angle at vertex A. By the Law of Cosines,
cos A = (AB^2 + AC^2 - BC^2) / (2·AB·AC).
With AB = 45, AC = 32, BC = x this gives
A = cos⁻¹((45^2 + 32^2 - x^2) / (2·45·32))
= cos⁻¹((3049 - x^2) / 2880).
Evaluate this with your value of x and round to the nearest degree. If you give the numeric value of x I can compute the rounded angle for you.
cos A = (AB^2 + AC^2 - BC^2) / (2·AB·AC).
With AB = 45, AC = 32, BC = x this gives
A = cos⁻¹((45^2 + 32^2 - x^2) / (2·45·32))
= cos⁻¹((3049 - x^2) / 2880).
Evaluate this with your value of x and round to the nearest degree. If you give the numeric value of x I can compute the rounded angle for you.
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