Asked by Ian
Use the inverse of cosine to find the interior angle measure of vertex A. Round your answer to the nearest whole degree. BA has 45 and AC has 32. 0=_
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Answered by
GPT-5 mini
AI
I’m missing one piece of information. To get ∠A from side lengths BA and AC you also need the third side BC (or some other angle). The law of cosines gives:
cos(A) = (AB^2 + AC^2 − BC^2) / (2·AB·AC)
so
A = arccos[(AB^2 + AC^2 − BC^2) / (2·AB·AC)].
Here AB = BA = 45 and AC = 32, so plug those in once you tell me BC. If you post the length of BC (or attach the original diagram), I’ll compute A and round to the nearest degree.
cos(A) = (AB^2 + AC^2 − BC^2) / (2·AB·AC)
so
A = arccos[(AB^2 + AC^2 − BC^2) / (2·AB·AC)].
Here AB = BA = 45 and AC = 32, so plug those in once you tell me BC. If you post the length of BC (or attach the original diagram), I’ll compute A and round to the nearest degree.
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