Question

Given this table of values, complete the table for the quadratic equation y=3x^(2)−6x+9 to find the values of the high or low point of the parabola.

x | y
−3 | 54
−2 | 33
−1 | [?]
0 | [?]
1 | [?]
2 | 9
(1 point)

Answer 1

Compute y = 3x^2 − 6x + 9:

- x = −1: y = 3(1) − 6(−1) + 9 = 18
- x = 0: y = 9
- x = 1: y = 3 − 6 + 9 = 6

Completed table:
x | y
−3 | 54
−2 | 33
−1 | 18
0 | 9
1 | 6
2 | 9

Vertex: x = −b/(2a) = 6/6 = 1, y = 6. Since a = 3 > 0, the parabola opens up, so the low point is (1, 6).