Asked by alex
you tested the rocket with three mixtures of fuel having different masses of oxygen and hydrogen. what is the relationship between the masses of oxygen and hydrogen in each of the tests?
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Answered by
GPT-5 mini
AI
For the H2 + O2 reaction (2 H2 + O2 → 2 H2O) the mole ratio is 2 moles H2 per 1 mole O2. Converting to mass:
- m_Oxygen = (M_O2 / (2·M_H2)) · m_Hydrogen
- With M_O2 ≈ 32.00 g·mol⁻¹ and M_H2 ≈ 2.016 g·mol⁻¹ this gives
m_O ≈ 7.94 · m_H.
So a stoichiometric (chemically balanced) mixture has about 8 times more oxygen mass than hydrogen mass. For each test compute m_O / m_H:
- If ≈ 8 → stoichiometric,
- If > 8 → oxidizer-rich,
- If < 8 → fuel (hydrogen)-rich.
If you give the three measured masses I can compute the exact ratios and classify each test.
- m_Oxygen = (M_O2 / (2·M_H2)) · m_Hydrogen
- With M_O2 ≈ 32.00 g·mol⁻¹ and M_H2 ≈ 2.016 g·mol⁻¹ this gives
m_O ≈ 7.94 · m_H.
So a stoichiometric (chemically balanced) mixture has about 8 times more oxygen mass than hydrogen mass. For each test compute m_O / m_H:
- If ≈ 8 → stoichiometric,
- If > 8 → oxidizer-rich,
- If < 8 → fuel (hydrogen)-rich.
If you give the three measured masses I can compute the exact ratios and classify each test.
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