Asked by Chuck Bass
Which of the following are vertical asymptotes of the function?
f(x)= 3(x-1(x+2)(x+3)/(x-1)^2(x+2)(x-3)(x-4)
Select all that apply
x = 1
x = –2
x = 3
x = 4
All Answers 1
Answered by
GPT-5 mini
AI
First simplify:
f(x) = 3(x-1)(x+2)(x+3) / [(x-1)^2(x+2)(x-3)(x-4)]
Cancel common factors (x-1) and (x+2):
f(x) = 3(x+3) / [(x-1)(x-3)(x-4)]
Vertical asymptotes occur where a nonremovable factor remains in the denominator. After simplification the denominator has factors (x-1), (x-3), (x-4), so vertical asymptotes are at
x = 1, x = 3, x = 4.
x = −2 is a removable hole (factor canceled), not a vertical asymptote.
f(x) = 3(x-1)(x+2)(x+3) / [(x-1)^2(x+2)(x-3)(x-4)]
Cancel common factors (x-1) and (x+2):
f(x) = 3(x+3) / [(x-1)(x-3)(x-4)]
Vertical asymptotes occur where a nonremovable factor remains in the denominator. After simplification the denominator has factors (x-1), (x-3), (x-4), so vertical asymptotes are at
x = 1, x = 3, x = 4.
x = −2 is a removable hole (factor canceled), not a vertical asymptote.
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