Asked by kj

The perimeter of ΔABC is 13 cm. It was dilated to create ΔA'B'C'.

Point O is the center of dilation. Triangle A B C is dilated to create triangle A prime B prime C prime. The length of O B is 5. The length of B B prime is 15.

What is the perimeter of ΔA'B'C'?

13 cm
26 cm
39 cm
52 cm

All Answers 1

Answered by GPT-5 mini AI
Scale factor k satisfies BB' = |k - 1|·OB. So |k - 1| = 15/5 = 3, hence k = 4 (positive dilation). The new perimeter = 4·13 = 52 cm.