Asked by kj
Line segment Z E is the angle bisector of AngleYEX and the perpendicular bisector of Line segment G F. Line segment G X is the angle bisector of AngleYGZ and the perpendicular bisector of Line segment E F. Line segment F Y is the angle bisector of AngleZFX and the perpendicular bisector of Line segment E G. Point A is the intersection of Line segment E Z, Line segment G X, and Line segment F Y.
Triangle G E F has angles with different measures. Point A is at the center. Lines are drawn from the points of the triangle to point A. Lines are drawn from point A to the sides of the triangle to form right angles and line segments A X, A Z, and A Y.
Which must be true?
Point A is the center of the circle that passes through points E, F, and G but is not the center of the circle that passes through points X, Y, and Z.
Point A is the center of the circle that passes through points X, Y, and Z but is not the center of the circle that passes through points E, F, and G.
Point A is the center of the circle that passes through points E, F, and G and the center of the circle that passes through points X, Y, and Z.
Point A is not necessarily the center of the circle that passes through points E, F, and G or the center of the circle that passes through points X, Y, and Z.
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Answer: Point A is the center of the circle that passes through points E, F, and G but is not the center of the circle that passes through points X, Y, and Z.
Reason: ZE, GX, FY are given as the perpendicular bisectors of GF, EF, and EG respectively. The perpendicular bisectors of the three sides of triangle EFG meet at the circumcenter, so A (their common intersection) is the circumcenter of triangle EFG — i.e., A is the center of the circle through E, F, G.
Those same three lines are given as angle bisectors of the angles formed by X, Y, Z, so they also concur at the incenter of triangle XYZ. In general (and in particular when the triangle GEF is not equilateral, as stated) the incenter of a triangle is not its circumcenter, so A need not be the center of the circle through X, Y, Z. Hence the first choice is correct.
Reason: ZE, GX, FY are given as the perpendicular bisectors of GF, EF, and EG respectively. The perpendicular bisectors of the three sides of triangle EFG meet at the circumcenter, so A (their common intersection) is the circumcenter of triangle EFG — i.e., A is the center of the circle through E, F, G.
Those same three lines are given as angle bisectors of the angles formed by X, Y, Z, so they also concur at the incenter of triangle XYZ. In general (and in particular when the triangle GEF is not equilateral, as stated) the incenter of a triangle is not its circumcenter, so A need not be the center of the circle through X, Y, Z. Hence the first choice is correct.
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