Asked by Void<3
Question 1
In a genetic research lab, you come across this completed Punnett Square.
Identify what information about the organism's genotype was used to complete this.
(1 point)
Responses
The organism’s genotype has a gene name “t”. One organism is Homozygous dominant for the trait and one is Homozygous recessive
The organism’s genotype has a gene name “t”. One organism is Homozygous dominant for the trait and one is Homozygous recessive
The organism’s genotype has a gene name “t”. One organism is Homozygous dominant for the trait and one is heterozygous
The organism’s genotype has a gene name “t”. One organism is Homozygous dominant for the trait and one is heterozygous
The organism’s genotype has a gene name “t”. Both organisms are heterozygous
The organism’s genotype has a gene name “t”. Both organisms are heterozygous
The organism’s genotype has a gene name “x”. One organism is Homozygous dominant for the trait and one is Homozygous recessive
All Answers 1
Answered by
GPT-5 mini
AI
I don’t see the Punnett square image in your message — could you upload or paste it?
If the four boxes in the completed square are TT, Tt, Tt, tt (one TT, two Tt, one tt), then the parents must have been Tt × Tt (both heterozygous). In that case the correct response is:
"The organism’s genotype has a gene name 't'. Both organisms are heterozygous."
If the boxes look different, here’s how to read them quickly:
- All boxes Tt → parents were TT × tt (one homozygous dominant, one homozygous recessive).
- Boxes TT and Tt only (no tt) → parents were TT × Tt (one homozygous dominant, one heterozygous).
- Boxes TT, Tt, Tt, tt → parents were Tt × Tt (both heterozygous).
Upload the square if you want me to pick the exact answer.
If the four boxes in the completed square are TT, Tt, Tt, tt (one TT, two Tt, one tt), then the parents must have been Tt × Tt (both heterozygous). In that case the correct response is:
"The organism’s genotype has a gene name 't'. Both organisms are heterozygous."
If the boxes look different, here’s how to read them quickly:
- All boxes Tt → parents were TT × tt (one homozygous dominant, one homozygous recessive).
- Boxes TT and Tt only (no tt) → parents were TT × Tt (one homozygous dominant, one heterozygous).
- Boxes TT, Tt, Tt, tt → parents were Tt × Tt (both heterozygous).
Upload the square if you want me to pick the exact answer.
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