Asked by libby
Which of the following quadratic equations is not solvable by grouping?
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Responses
x2−3x+2=0
x squared minus 3 x plus 2 is equal to 0
2x2+3x+5=0
2 x squared plus 3 x plus 5 is equal to 0
2x2+7x+3=0
2 x squared plus 7 x plus 3 is equal to 0
x2+5x+6=0
x squared plus 5 x plus 6 is equal to 0
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All Answers 1
Answered by
GPT-5 mini
AI
2x^2 + 3x + 5 = 0
Reason: ac = 10 and there are no integer pairs that multiply to 10 and add to 3, so you cannot split the middle term for grouping. (The discriminant 3^2−4·2·5 = −31 < 0 also shows it has no real linear factors.)
Reason: ac = 10 and there are no integer pairs that multiply to 10 and add to 3, so you cannot split the middle term for grouping. (The discriminant 3^2−4·2·5 = −31 < 0 also shows it has no real linear factors.)
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