a 1250 kg car is pulling a 325 kb trailer. The car and trailer have an acceleration of 2,15m/sec2 together. Determine the net force on the ca-trailer combination. What is the net force on the railer?

Answer 1

(Fc + Ft) = (Mc + Mt )*a,
= (1250 + 325) * 2.15,
= 1575 * 2.15 = 3386.25 N.

Fc = (1250 / 325)*Ft = 3.85Ft,
3.85Ft + Ft = 3386.25 N,
4.85Ft = 3386.25,
Ft = 3386.25 / 325 = 698.8 N = Force on the trailer.

Fc = 3.85 * 698.8 = 2687.5 N = Force on the car.(not required).