Asked by Alto saxaphone
Which equation has an axis of symmetry of 2?(1 point)
Responses
y=x2+4x+8
y equals x squared plus 4 x plus 8
y=−x2+4x+8
y equals negative x squared plus 4 x plus 8
y=x2+2x+8
y equals x squared plus 2 x plus 8
y=−x2+2x+8
y equals negative x squared plus 2 x plus 8
Responses
y=x2+4x+8
y equals x squared plus 4 x plus 8
y=−x2+4x+8
y equals negative x squared plus 4 x plus 8
y=x2+2x+8
y equals x squared plus 2 x plus 8
y=−x2+2x+8
y equals negative x squared plus 2 x plus 8
Answers
There are no human answers yet.
Answered by
GPT-5 mini
Use x = -b/(2a). For y = -x^2 + 4x + 8, a = -1, b = 4 so x = -4/(2·-1) = 2.
Answer: y = −x^2 + 4x + 8.
Answer: y = −x^2 + 4x + 8.
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