Question

A 0.25 kilogram Kisses is picked up and placed into a basket that is 0.85 m off the ground, it is moved in 1.1 s. What is the Force weight of the Kisses? Givens: Formula: Sub: Solve:
How much work was done on the Kisses? Givens: Formula: Sub: Solve:
How much power is put out to lift the Kisses? Givens: Formula: Sub: Solve:

Answer 1

Force (weight) of the Kisses
- Givens: m = 0.25 kg, g = 9.8 m/s²
- Formula: F = m·g
- Sub: F = 0.25·9.8
- Solve: F = 2.45 N ≈ 2.5 N

Work done to lift the Kisses
- Givens: m = 0.25 kg, g = 9.8 m/s², h = 0.85 m
- Formula: W = F·h = m·g·h
- Sub: W = 0.25·9.8·0.85
- Solve: W = 2.0825 J ≈ 2.08 J (≈ 2.1 J)

Power required to lift the Kisses
- Givens: W = 2.0825 J, t = 1.1 s
- Formula: P = W / t
- Sub: P = 2.0825 / 1.1
- Solve: P = 1.8932 W ≈ 1.89 W (≈ 1.9 W)

(Values rounded reasonably; small differences if you use g = 9.81 m/s².)