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A 5.2 kg candy heart stands at the top of a 2.4 m high table. What is the potential energy of the candy? What is the Work done? Givens: Formula: Sub: Solve:
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Givens:
- m = 5.2 kg
- h = 2.4 m
- g = 9.8 m/s²
Formula:
- Gravitational potential energy: U = m g h
Sub:
- U = (5.2 kg)(9.8 m/s²)(2.4 m)
Solve:
- U = 122.3 J ≈ 1.22 × 10^2 J (≈ 122 J)
Work done:
- If the candy falls to the floor, gravity does +122 J of work (the potential energy decreases by 122 J).
- Conversely, raising the candy from the floor to the table requires +122 J of work by an external agent. If the candy simply sits on the table with no displacement, no work is done.
- m = 5.2 kg
- h = 2.4 m
- g = 9.8 m/s²
Formula:
- Gravitational potential energy: U = m g h
Sub:
- U = (5.2 kg)(9.8 m/s²)(2.4 m)
Solve:
- U = 122.3 J ≈ 1.22 × 10^2 J (≈ 122 J)
Work done:
- If the candy falls to the floor, gravity does +122 J of work (the potential energy decreases by 122 J).
- Conversely, raising the candy from the floor to the table requires +122 J of work by an external agent. If the candy simply sits on the table with no displacement, no work is done.
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