Asked by lee
Hello Reiny, please check these problems for me and if they are not right WOULD YOU PLEASE HELP ME WITH THE CORRECT ONES THANKS!!!
1. Slove for X, wher X is the real number, square root 5x + 9= square root 9x + 13= 27
2. Find the value: ^3 square root -27= 9
3. Write the following in simplified radical form ^4 square root 80= 4
PLEASE HELP QUICKLY!!
1. Slove for X, wher X is the real number, square root 5x + 9= square root 9x + 13= 27
2. Find the value: ^3 square root -27= 9
3. Write the following in simplified radical form ^4 square root 80= 4
PLEASE HELP QUICKLY!!
Answers
Answered by
Reiny
1 . I assume you meant
√(5x+9) = √(9x+13)
if so, then square both sides
5x + 9 = 9x + 13
-4x = 4
x = -1, the answer checks in my equation
2. I can't figure out what you are saying.
are you finding the cuberoot of -27 ?
if so, the cuberoot of -27 = -3
3 again, is that supposed to the fourth root of 80 ?
80^(1/4) = (16)^(1/4) (5)^(1/4)
= 2 times cuberoot of 5
√(5x+9) = √(9x+13)
if so, then square both sides
5x + 9 = 9x + 13
-4x = 4
x = -1, the answer checks in my equation
2. I can't figure out what you are saying.
are you finding the cuberoot of -27 ?
if so, the cuberoot of -27 = -3
3 again, is that supposed to the fourth root of 80 ?
80^(1/4) = (16)^(1/4) (5)^(1/4)
= 2 times cuberoot of 5
Answered by
Reiny
last line should have said
2 times fourthroot of 5
2 times fourthroot of 5
Answered by
lee
THANKS AGAIN Reiny!!
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