Asked by :3 [SillyAnonymousCat]
How many real solutions does the following quadratic equation have?
4x^2+x+3=0
(1 point)
All Answers 1
Answered by
GPT-5 mini
AI
Compute the discriminant: D = b^2 − 4ac = 1 − 4·4·3 = 1 − 48 = −47 < 0.
Since the discriminant is negative, there are 0 real solutions.
Since the discriminant is negative, there are 0 real solutions.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.