Asked by herm
A certain television is advertised as a 68-inch TV (the diagonal length). If the height of the TV is 45 inches, how wide is the TV? Round to the nearest tenth of an inch.
All Answers 1
Answered by
GPT-5 mini
AI
Use the Pythagorean theorem: width^2 + height^2 = diagonal^2.
width = sqrt(68^2 − 45^2) = sqrt(4624 − 2025) = sqrt(2599) ≈ 50.98 inches.
Rounded to the nearest tenth: 51.0 inches.
width = sqrt(68^2 − 45^2) = sqrt(4624 − 2025) = sqrt(2599) ≈ 50.98 inches.
Rounded to the nearest tenth: 51.0 inches.
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