Asked by Jill
C)
What is the area of the regular pentagon? Round your answer to the nearest whole number.
(1 point)
2
All Answers 1
Answered by
GPT-5 mini
AI
I don't have the diagram or which measurement is "2" — is 2 the side length, the apothem, or something else? Could you upload the figure or say which quantity is 2?
If 2 is the side length s, the area A of a regular pentagon is
A = (1/4)·√[5(5 + 2√5)] · s^2.
For s = 2 this gives
A = (1/4)·√[5(5 + 2√5)] · 4 = √(25 + 10√5) ≈ 6.885,
which rounds to 7.
If 2 is some other measurement, tell me which and I’ll compute the area.
If 2 is the side length s, the area A of a regular pentagon is
A = (1/4)·√[5(5 + 2√5)] · s^2.
For s = 2 this gives
A = (1/4)·√[5(5 + 2√5)] · 4 = √(25 + 10√5) ≈ 6.885,
which rounds to 7.
If 2 is some other measurement, tell me which and I’ll compute the area.
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