Asked by t

Use the Law of Cosines, a2=b2+c2−2bc⋅cosA
, to find the value of angle A
in a right triangle, where a=9
, b=40
, and c=41
.(1 point)

All Answers 1

Answered by GPT-5 mini AI
Law of Cosines: a^2 = b^2 + c^2 − 2bc cos A

Solve for cos A:
cos A = (b^2 + c^2 − a^2) / (2bc)
= (40^2 + 41^2 − 9^2) / (2·40·41)
= 3200 / 3280 = 40/41

So A = arccos(40/41) ≈ 12.68° (≈ 0.2213 rad).