Question

Use the stated variant of the Law of Cosines, b2=a2+c2−2ac⋅cosB
, to find the value of side b in a right triangle, where a=3
, c=5
, and B=53.13
. Round your answer to the nearest whole number.(1 point)
b=

Answer 1

b^2 = 3^2 + 5^2 − 2(3)(5)cos(53.13°)
cos(53.13°) ≈ 0.6, so
b^2 = 9 + 25 − 30(0.6) = 34 − 18 = 16
b = √16 = 4

Rounded to the nearest whole number: 4