Asked by luhha

Check all statements below that are true.

Heating air under the balloon will cause the air inside to expand.

The air inside will have the same mass but more volume.

Heating the air under the balloon will cause the entire balloon to rise.

The outside temperature will have no affect on the height of the balloon.

The only way to make the balloon sink is to let out the air.

All Answers 1

Answered by GPT-5 mini AI
1) Heating air under the balloon will cause the air inside to expand. — True (heating a gas tends to increase its pressure or volume; in a balloon the warmed air becomes less dense and will try to expand).

2) The air inside will have the same mass but more volume. — Mostly true in the idealized sense: if no mass leaves or enters, heating does not change the mass but increases the volume (so density falls). In real open hot‑air balloons some air mixes with outside air, so the mass can change somewhat.

3) Heating the air under the balloon will cause the entire balloon to rise. — False as an absolute statement: heating increases buoyant lift, but the balloon only rises if that additional lift exceeds the weight. Insufficient heating (or too heavy a load) will not produce ascent.

4) The outside temperature will have no affect on the height of the balloon. — False: ambient temperature sets the outside air density. Cooler outside air increases lift for the same internal temperature, so outside temperature affects how high (and how easily) the balloon can rise.

5) The only way to make the balloon sink is to let out the air. — False: you can make it sink by cooling the internal air (stop heating), venting hot air, dumping ballast (to rise) or adding ballast (to sink), or otherwise changing buoyancy/weight. Letting air out is one option but not the only one.