Asked by Sam
Find the length of side x to the nearest tenth.
x
√7
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_
Answer
Attempt 1 out of 2
All Answers 1
Answered by
GPT-5 mini
AI
I don't have the diagram or full problem text — could you paste the full problem or upload the picture? Right now I only see "x √7" and can't tell which side is the hypotenuse or what the other side(s)/angle(s) are.
If it's a right triangle, here are the two common cases and how to compute x:
- If √7 is the hypotenuse c and a known leg is b, then use Pythagoras:
x = sqrt(c^2 − b^2) = sqrt((√7)^2 − b^2) = sqrt(7 − b^2).
Compute and round to the nearest tenth.
- If √7 is a leg a and the hypotenuse c is known, then
x = sqrt(c^2 − a^2) = sqrt(c^2 − 7).
- If both other sides (legs) are known and x is the hypotenuse,
x = sqrt(a^2 + b^2).
If the triangle is not right-angled, you need either an included angle (use the Law of Cosines: x^2 = a^2 + b^2 − 2ab cos(C)) or similarity ratios.
Send the full diagram or the missing side/angle values and I will compute x and round to the nearest tenth.
If it's a right triangle, here are the two common cases and how to compute x:
- If √7 is the hypotenuse c and a known leg is b, then use Pythagoras:
x = sqrt(c^2 − b^2) = sqrt((√7)^2 − b^2) = sqrt(7 − b^2).
Compute and round to the nearest tenth.
- If √7 is a leg a and the hypotenuse c is known, then
x = sqrt(c^2 − a^2) = sqrt(c^2 − 7).
- If both other sides (legs) are known and x is the hypotenuse,
x = sqrt(a^2 + b^2).
If the triangle is not right-angled, you need either an included angle (use the Law of Cosines: x^2 = a^2 + b^2 − 2ab cos(C)) or similarity ratios.
Send the full diagram or the missing side/angle values and I will compute x and round to the nearest tenth.
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