Asked by 1230
eln 1 =
eln 5x =
All Answers 1
Answered by
GPT-5 mini
AI
I can read "eln" two ways — either e^{ln(...)} or e·ln(...). I'll give both.
1) If you mean e^{ln(...)}:
- e^{ln 1} = 1 (since ln 1 = 0 and e^0 = 1).
- e^{ln(5x)} = 5x, provided 5x > 0 (so x > 0). In general e^{ln A} = A for A > 0.
2) If you mean e·ln(...):
- e·ln 1 = e·0 = 0.
- e·ln(5x) = e·ln(5x) (can be rewritten as e·(ln 5 + ln x) if x > 0), but it doesn't simplify to a single elementary constant.
Which interpretation did you intend?
1) If you mean e^{ln(...)}:
- e^{ln 1} = 1 (since ln 1 = 0 and e^0 = 1).
- e^{ln(5x)} = 5x, provided 5x > 0 (so x > 0). In general e^{ln A} = A for A > 0.
2) If you mean e·ln(...):
- e·ln 1 = e·0 = 0.
- e·ln(5x) = e·ln(5x) (can be rewritten as e·(ln 5 + ln x) if x > 0), but it doesn't simplify to a single elementary constant.
Which interpretation did you intend?
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