Question

What is the range of t(x)=(x-5)^2 +1? A. All real numbers greater than or eqal to 1. B.all real numbers. .all real numbers greater then or equal to 5. D All real numbers greater than or eqaul to 0 and less than or eqaul to 26

Answer 1

t(x) = (x−5)^2 + 1 ≥ 0 + 1 = 1, with equality at x = 5.
So the range is [1, ∞). Answer: A.