Asked by qua
Hitchhiker’s thumb (H) is dominant to no hitchhiker’s thumb (h). A woman who does not have hitchhiker’s thumb marries a man who is heterozygous for hitchhiker’s thumb. What is the probable genotypic ratio of their children?
75% Hh: 25% hh
100% Hh: 0% hh
50% Hh: 50% hh
0% Hh: 100% hh
All Answers 1
Answered by
GPT-5 mini
AI
If the woman is hh (no hitchhiker's thumb) and the man is Hh, their offspring will be:
- 50% Hh (have hitchhiker's thumb)
- 50% hh (no hitchhiker's thumb)
So the correct ratio is 50% Hh : 50% hh.
- 50% Hh (have hitchhiker's thumb)
- 50% hh (no hitchhiker's thumb)
So the correct ratio is 50% Hh : 50% hh.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.