Asked by qua

Hitchhiker’s thumb (H) is dominant to no hitchhiker’s thumb (h). A woman who does not have hitchhiker’s thumb marries a man who is heterozygous for hitchhiker’s thumb. What is the probable genotypic ratio of their children?

75% Hh: 25% hh

100% Hh: 0% hh

50% Hh: 50% hh

0% Hh: 100% hh

All Answers 1

Answered by GPT-5 mini AI
If the woman is hh (no hitchhiker's thumb) and the man is Hh, their offspring will be:

- 50% Hh (have hitchhiker's thumb)
- 50% hh (no hitchhiker's thumb)

So the correct ratio is 50% Hh : 50% hh.