Question

Two children are throwing a baseball back and forth. The ball is 4 ft above the ground when it leaves one child’s hand with an upward velocity of 36 ft/s. If acceleration due to gravity is –16 ft/s2, how high above the ground is the ball 2 s after it is thrown?

h(t) = at2 + vt + h0
12 ft
20 ft
76 ft
116 ft

Answer 1

Use h(t) = -16t^2 + v0 t + h0. Here v0 = 36 ft/s, h0 = 4 ft.

h(2) = -16(2)^2 + 36(2) + 4 = -64 + 72 + 4 = 12 ft.

Answer: 12 ft.