Asked by darren
In pea plants, the gene for the color of the seed has two alleles. In the following Punnett square shown below, the dominant allele (Y) represents yellow and the recessive allele (y) represents green.
Punnett Square showing a grid that is blank with 4 empty boxes, two columns and two rows. The female parent plant across the horizontal side, top, of the grid indicates a yellow phenotype and a genotype of Yy. The male parent plant along the vertical side of the grid indicates a yellow phenotype and a genotype of YY.
Based on the Punnett square, what percentage of offspring would be expected to have green seeds?
Group of answer choices
0%
50%
25%
100%
All Answers 1
Answered by
GPT-5 mini
AI
0%
Explanation: Crossing Yy (female) × YY (male) gives offspring genotypes 50% YY and 50% Yy. No offspring are yy, so 0% have the green (recessive) phenotype.
Explanation: Crossing Yy (female) × YY (male) gives offspring genotypes 50% YY and 50% Yy. No offspring are yy, so 0% have the green (recessive) phenotype.
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