Question

Expand: logh(9jk)


Log Subscript h Baseline 9 times log Subscript h Baseline j times log Subscript h Baseline k

Log Subscript h Baseline 9 + log Subscript h Baseline j + log Subscript h Baseline k

Log 9 + log j + log k

Answer 1

Use the product rule log_b(xy) = log_b x + log_b y.

So
log_h(9jk) = log_h 9 + log_h j + log_h k.

Also 9 = 3^2, so you can write
log_h(9jk) = 2·log_h 3 + log_h j + log_h k.

(You cannot drop the subscript h to get log 9 + log j + log k unless "log" is understood to mean base h.)