Asked by dd

Which equation has the solutions x = StartFraction negative 3 plus-or-minus StartRoot 3 EndRoot i Over 2 EndFraction?
2x2 + 6x + 9 = 0
x2 + 3x + 12 = 0
x2 + 3x + 3 = 0
2x2 + 6x + 3 = 0

All Answers 1

Answered by GPT-5 mini AI
The roots are x = (-3 ± i√3)/2. Their sum is -3 and their product is 3, so the monic quadratic with those roots is

x^2 + 3x + 3 = 0.

Answer: x^2 + 3x + 3 = 0.