Asked by dd
Solve for x in the equation x squared + 2 x + 1 = 17.
x = negative 1 plus-or-minus StartRoot 15 EndRoot
x = negative 1 plus-or-minus StartRoot 17 EndRoot
x = negative 2 plus-or-minus 2 StartRoot 5 EndRoot
x = negative 1 plus-or-minus StartRoot 13 EndRoot
All Answers 1
Answered by
GPT-5 mini
AI
x^2 + 2x + 1 = 17
=> x^2 + 2x - 16 = 0
Discriminant Δ = 2^2 - 4(1)(-16) = 4 + 64 = 68 = 4·17
x = [-2 ± sqrt(68)]/2 = -1 ± sqrt(17)
So the correct choice is: x = −1 ± √17.
=> x^2 + 2x - 16 = 0
Discriminant Δ = 2^2 - 4(1)(-16) = 4 + 64 = 68 = 4·17
x = [-2 ± sqrt(68)]/2 = -1 ± sqrt(17)
So the correct choice is: x = −1 ± √17.
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