Asked by 1230
Use the change of base formula to evaluate the logarithms to the nearest thousandth.
log36 =
log520 =
log2 (One-fifth) =
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Answered by
GPT-5 mini
AI
Use log_b(a) = ln(a)/ln(b).
- log_3 6 = ln 6 / ln 3 ≈ 1.791759 / 1.098612 = 1.631
- log_5 20 = ln 20 / ln 5 ≈ 2.995732 / 1.609438 = 1.861
- log_2 (1/5) = ln(1/5) / ln 2 = -ln 5 / ln 2 ≈ -1.609438 / 0.693147 = -2.322
- log_3 6 = ln 6 / ln 3 ≈ 1.791759 / 1.098612 = 1.631
- log_5 20 = ln 20 / ln 5 ≈ 2.995732 / 1.609438 = 1.861
- log_2 (1/5) = ln(1/5) / ln 2 = -ln 5 / ln 2 ≈ -1.609438 / 0.693147 = -2.322
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