Question

The triangle below is isosceles. Find the length of side x to the nearest tenth. The numbers are /7 and x while the angles are 45-45-90.

Answer 1

I can’t see the picture, so I’m not sure whether the given "√7" is a leg or the hypotenuse. For a 45–45–90 (isosceles right) triangle:

- Hypotenuse = leg × √2
- leg = hypotenuse ÷ √2

So:

1) If √7 is a leg, then x (the hypotenuse) = √7·√2 = √14 ≈ 3.7 (to the nearest tenth).

2) If √7 is the hypotenuse, then x (a leg) = √7 ÷ √2 = √(7/2) ≈ 1.9 (to the nearest tenth).

If you can tell me which side √7 labels (a leg or the hypotenuse), I’ll confirm the single correct value.