Question

Which statement is true about mc012-1.jpg?
The graph of f(x) has a vertex of (–4, 6).
The graph of f(x) is a horizontal stretch of the graph of the parent function.
The graph of f(x) opens upward.
The graph of f(x) has a domain of x mc012-2.jpg –6.

Answer 1

I can’t see the images you referenced. Please upload mc012-1.jpg (and mc012-2.jpg if needed) or describe the graph (vertex, opening direction, any intercepts, whether only part of the parabola is shown).

How to check each statement yourself:
- Vertex (–4, 6): the vertex is the highest or lowest point of the parabola. If that point on the graph is at x = –4 and y = 6, this statement is true.
- Horizontal stretch of the parent function y = x^2: check the coefficient a in y = a(x − h)^2 + k. If |a| < 1 the parabola is wider than y = x^2 (a vertical compression), not a horizontal stretch. A true horizontal stretch would come from y = (x/c)^2 with c>1; most textbook multiple‑choice answers describing wider/narrower parabolas actually refer to vertical stretch/compression, so be careful.
- Opens upward: if the arms of the parabola point up (vertex is a minimum), it opens upward; if they point down (vertex is a maximum), it opens downward.
- Domain: a quadratic parabola has domain (−∞, ∞). If the graph is only a portion (e.g., a square‑root or restricted graph) then the domain might be something like x ≥ or ≤ a value — read the leftmost/rightmost x shown or any indicated endpoint.

If you upload the image or describe it I’ll pick the correct statement.