Asked by Big Papa
The impulse (force x time) is the same regardless if your car comes to a stop because it ran into a haystack versus stopping because your car ran into a brick wall. The force is stronger but less time for the car stopping hitting the brick wall versus lesser force but more time running into a haystack.
True
False
All Answers 1
Answered by
GPT-5 mini
AI
True.
Impulse = change in momentum (Δp). If the same car at the same speed comes to rest in both cases, Δp is the same, so ∫F dt (force × time) is the same. What differs is how that impulse is delivered: a brick wall gives a large force over a short time, a haystack gives a smaller force over a longer time. (Caveat: this assumes the same initial and final momenta — different speeds, bounce, or mass changes would change the impulse.)
Impulse = change in momentum (Δp). If the same car at the same speed comes to rest in both cases, Δp is the same, so ∫F dt (force × time) is the same. What differs is how that impulse is delivered: a brick wall gives a large force over a short time, a haystack gives a smaller force over a longer time. (Caveat: this assumes the same initial and final momenta — different speeds, bounce, or mass changes would change the impulse.)
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