Asked by cvf
What is the following quotient?
StartFraction 2 minus StartRoot 8 EndRoot Over 4 + StartRoot 12 EndRoot EndFraction
StartFraction StartRoot 3 EndRoot minus StartRoot 6 EndRoot Over 4 EndFraction
StartFraction 2 + StartRoot 3 EndRoot minus 2 StartRoot 2 EndRoot minus StartRoot 6 EndRoot Over 4 EndFraction
2 minus StartRoot 3 EndRoot minus 2 StartRoot 2 EndRoot + StartRoot 6 EndRoot
StartFraction negative 2 minus StartRoot 3 EndRoot + 2 StartRoot 2 EndRoot + StartRoot 6 EndRoot Over 2 EndFraction
All Answers 1
Answered by
GPT-5 mini
AI
Interpret the quotient as
[(2 − √8)/(4 + √12)] ÷ [(√3 − √6)/4].
Simplify radicals: √8 = 2√2, √12 = 2√3. Then
(2 − √8)/(4 + √12) = (2 − 2√2)/(4 + 2√3) = (1 − √2)/(2 + √3).
Also √3 − √6 = √3(1 − √2), so (√3 − √6)/4 = √3(1 − √2)/4.
Thus the quotient is
[(1 − √2)/(2 + √3)] · [4/(√3(1 − √2))] = 4/(√3(2 + √3)).
Rationalize:
4/(√3(2 + √3)) · (2 − √3)/(2 − √3) = 4(2 − √3)/√3
= (8√3 − 12)/3 = (4(2√3 − 3))/3.
So the quotient = (8√3 − 12)/3 (or 4(2√3 − 3)/3).
[(2 − √8)/(4 + √12)] ÷ [(√3 − √6)/4].
Simplify radicals: √8 = 2√2, √12 = 2√3. Then
(2 − √8)/(4 + √12) = (2 − 2√2)/(4 + 2√3) = (1 − √2)/(2 + √3).
Also √3 − √6 = √3(1 − √2), so (√3 − √6)/4 = √3(1 − √2)/4.
Thus the quotient is
[(1 − √2)/(2 + √3)] · [4/(√3(1 − √2))] = 4/(√3(2 + √3)).
Rationalize:
4/(√3(2 + √3)) · (2 − √3)/(2 − √3) = 4(2 − √3)/√3
= (8√3 − 12)/3 = (4(2√3 − 3))/3.
So the quotient = (8√3 − 12)/3 (or 4(2√3 − 3)/3).
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