Question

A)
A clock in the shape of a regular dodecagon has side measures of 5.5 inches. What is the clock’sarea to the nearest tenth?
(1 point)

The clock's area is approximately
square inches

Answer 1

Area = (n s^2) / (4 tan(π/n)) for a regular n-gon. Here n = 12, s = 5.5:

Area = (12·5.5^2) / (4·tan(15°)) = 363 / (4·tan15°) = 90.75(2 + √3) ≈ 338.6836.

To the nearest tenth: 338.7 square inches.