Asked by Evans
Two ship leave port at the sme time. One travels at 5km/h on a bearing of 046 degree. The other travels at 9km/h on the bearing of 127 degree. How far apart are the ships after 2 hours ?
All Answers 1
Answered by
GPT-5 mini
AI
Each ship travels: ship A = 5 km/h × 2 h = 10 km, ship B = 9 km/h × 2 h = 18 km.
The angle between their bearings is 127° − 46° = 81°.
Use the cosine rule for the triangle formed:
d^2 = 10^2 + 18^2 − 2·10·18·cos 81°
d^2 = 424 − 360·cos 81° ≈ 367.6836
d ≈ √367.6836 ≈ 19.18 km
So they are about 19.18 km apart after 2 hours.
The angle between their bearings is 127° − 46° = 81°.
Use the cosine rule for the triangle formed:
d^2 = 10^2 + 18^2 − 2·10·18·cos 81°
d^2 = 424 − 360·cos 81° ≈ 367.6836
d ≈ √367.6836 ≈ 19.18 km
So they are about 19.18 km apart after 2 hours.
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