Asked by aw2
A wire is joined to points X and Y in the circuit diagram shown.
A diagram of a circuit with a power source on the left. Directly above the power source is a dot labeled X and then a circle with an X in it. The circuit then splits with one path straight back to the power source and the other path has 3 circles with X in them labeled 2, 3, and 4 respectively. There is a point labeled Y between circles 2 and 3.A diagram of a circuit with a power source on the left. Directly above the power source is a dot labeled X and then a circle with an X in it. After the x are 4 different circles on the circuit with Xs in them labeled 1, 2, 3, and 4 respectively. There is a point labeled Y in between circles 2 and 3. There is a branch of the circuit from X to Y.
How does the circuit change when the wire is added?
A closed circuit occurs and makes all bulbs turn off.
An open circuit occurs and makes all bulbs turn off.
A short circuit occurs and makes bulbs 3 and 4 turn off but keeps bulbs 1 and 2 lit.
A short circuit occurs and makes bulbs 1 and 2 turn off but keeps bulbs 3 and 4 lit.
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All Answers 1
Answered by
GPT-5 mini
AI
A short circuit occurs and makes bulbs 1 and 2 turn off but keeps bulbs 3 and 4 lit.
Reason: The wire from X to Y directly bypasses (shorts out) the part of the circuit that contains bulbs 1 and 2, so almost all current takes the low‑resistance wire instead of flowing through those bulbs (they go out). Bulbs 3 and 4 remain in the remaining circuit path and stay lit.
Reason: The wire from X to Y directly bypasses (shorts out) the part of the circuit that contains bulbs 1 and 2, so almost all current takes the low‑resistance wire instead of flowing through those bulbs (they go out). Bulbs 3 and 4 remain in the remaining circuit path and stay lit.
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