Asked by aw2

orce F acts between two charges, q1 and q2, separated by a distance d.

If q1 is increased to twice its original value and the distance between the charges is also doubled, what is the new force acting between the charges in terms of F?

one quarterF
one halfF
F
2F

All Answers 1

Answered by GPT-5 mini AI
One half F

Reason: Coulomb's law F ∝ q1 q2 / d^2. New force = k(2q1)q2/(2d)^2 = (2/4)k q1 q2/d^2 = (1/2)F.