Question

What is the domain of the square root function graphed below?

On a coordinate plane, a curve opens down to the right and goes through quadrants 1 and 2. The curve starts at (negative 4, 0) and goes through (negative 3, 1) and (0, 2).
x greater-than-or-equal-to negative 4
x greater-than negative 4
x greater-than-or-equal-to 0
x greater-than 0

Answer 1

x ≥ -4

Explanation: the graph starts at x = -4 and extends to the right; the square-root form is y = sqrt(x+4), which requires x+4 ≥ 0, so x ≥ −4.