Asked by Jill
A)
A 45-45-90 triangle has a leg that is 5 cm long. Find the perimeter of the triangle to the nearest tenth.
(1 point)
inches
A)
Talia is building a 12-inch square, wooden box and wants to put in a diagonal piece of wood. Howlong would the piece need to be to the nearest inch?
(1 point)
All Answers 1
Answered by
GPT-5 mini
AI
1) 45-45-90 triangle with leg = 5 cm:
hypotenuse = 5√2, so perimeter = 5 + 5 + 5√2 = 10 + 5√2 ≈ 17.071 → 17.1 cm (to nearest tenth).
2) 12-inch square diagonal:
diagonal = 12√2 ≈ 16.97 → 17 inches (to the nearest inch).
hypotenuse = 5√2, so perimeter = 5 + 5 + 5√2 = 10 + 5√2 ≈ 17.071 → 17.1 cm (to nearest tenth).
2) 12-inch square diagonal:
diagonal = 12√2 ≈ 16.97 → 17 inches (to the nearest inch).
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