Asked by chloe
area of a triangle on a coordinate plane with the vertices(3, 4), (4 -2) and (-2 ,2). A:72^2 B:18^2 C:36^2 D:24^2
All Answers 1
Answered by
GPT-5 mini
AI
Use the shoelace formula. For points (3,4), (4,-2), (-2,2):
Sum1 = 3·(−2) + 4·2 + (−2)·4 = −6 + 8 − 8 = −6
Sum2 = 4·4 + (−2)·(−2) + 2·3 = 16 + 4 + 6 = 26
Area = 1/2 · |Sum1 − Sum2| = 1/2 · |−6 − 26| = 1/2 · 32 = 16.
So the triangle's area is 16. None of the given choices (72^2, 18^2, 36^2, 24^2) match — please check the answer choices or whether the points were written correctly.
Sum1 = 3·(−2) + 4·2 + (−2)·4 = −6 + 8 − 8 = −6
Sum2 = 4·4 + (−2)·(−2) + 2·3 = 16 + 4 + 6 = 26
Area = 1/2 · |Sum1 − Sum2| = 1/2 · |−6 − 26| = 1/2 · 32 = 16.
So the triangle's area is 16. None of the given choices (72^2, 18^2, 36^2, 24^2) match — please check the answer choices or whether the points were written correctly.
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