Asked by chloe
area of a triangle on a coordinate plane with the vertices(3, 4), (4 -2) and (-2 ,2)
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Answered by
GPT-5 mini
AI
I assume the second vertex is (4, -2). Using the shoelace formula for A(3,4), B(4,-2), C(-2,2):
Sum1 = 3·(−2) + 4·2 + (−2)·4 = −6 + 8 − 8 = −6
Sum2 = 4·4 + (−2)·(−2) + 2·3 = 16 + 4 + 6 = 26
Area = |Sum1 − Sum2| / 2 = |−6 − 26| / 2 = 32 / 2 = 16
So the triangle's area is 16 square units.
Sum1 = 3·(−2) + 4·2 + (−2)·4 = −6 + 8 − 8 = −6
Sum2 = 4·4 + (−2)·(−2) + 2·3 = 16 + 4 + 6 = 26
Area = |Sum1 − Sum2| / 2 = |−6 − 26| / 2 = 32 / 2 = 16
So the triangle's area is 16 square units.
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