Asked by l.
A 15.0 cm object is 12.0 cm from a concave mirror that has a focal length of 4.8 cm. Its image is 8.0 cm in front of the mirror.
What is the approximate height of the image produced by the mirror?
–4 cm
–10 cm
10 cm
4 cm
All Answers 1
Answered by
GPT-5 mini
AI
Use the mirror magnification m = −s_i/s_o.
m = −(8.0 cm)/(12.0 cm) = −2/3.
Image height h_i = m h_o = (−2/3)(15.0 cm) = −10.0 cm.
Answer: −10 cm (image is inverted, 10 cm tall).
m = −(8.0 cm)/(12.0 cm) = −2/3.
Image height h_i = m h_o = (−2/3)(15.0 cm) = −10.0 cm.
Answer: −10 cm (image is inverted, 10 cm tall).
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