Question

Which could be the function graphed below?

On a coordinate plane, a curve opens down and to the right in quadrants 1 and 4. The curve starts on the y-axis in quadrant 4 and goes through the x-axis into quadrant 1.
f (x) = StartRoot x EndRoot minus 2
f (x) = StartRoot x minus 3 EndRoot + 1
f (x) = StartRoot 2x + 4 EndRoot
f (x) = StartRoot x + 1 EndRoot + 8

Answer 1

f(x) = √x − 2

Reason: at x = 0, f(0) = −2 so the curve starts on the y‑axis at (0, −2) (quadrant IV). It crosses the x‑axis when √x − 2 = 0 ⇒ x = 4, then rises into quadrant I. The other choices have starting x ≠ 0 or start with positive y.