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A vector in medium 1 with an index of refraction of 1.92 is at an angle of 30 degrees. Into medium 2 with an index of refraction of 1.0003 it is at an unknown angle.
What is the angle of refraction?
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Use Snell's law: n1 sinθ1 = n2 sinθ2.
sinθ2 = (n1/n2) sinθ1 = (1.92/1.0003) * sin 30° = 0.96/1.0003 ≈ 0.959712.
θ2 = arcsin(0.959712) ≈ 73.9° (about 74°).
(There is no total internal reflection here since sinθ1 = 0.5 < n2/n1 ≈ 0.521.)
sinθ2 = (n1/n2) sinθ1 = (1.92/1.0003) * sin 30° = 0.96/1.0003 ≈ 0.959712.
θ2 = arcsin(0.959712) ≈ 73.9° (about 74°).
(There is no total internal reflection here since sinθ1 = 0.5 < n2/n1 ≈ 0.521.)
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