Question

What is the energy of a photon of infrared radiation with a frequency of 2.53 × 1012 Hz? Planck’s constant is
6.63 × 10–34 J • s.

1.68 × 1023 J
1.68 × 1047 J
1.68 × 10–21 J
1.68 × 10–45 J

Answer 1

E = hν = (6.63×10⁻³⁴ J·s)(2.53×10¹² s⁻¹) = 1.68×10⁻²¹ J.

Answer: 1.68 × 10⁻²¹ J.