Asked by tt
An automobile tire at 30.0°C has a pressure of 3.00 atm. The temperature decreases to -5.00°C. Assume that there is no volume change in the tire.
Formula to use:
P1
T1
=
P2
T2
How does the tire pressure change in response to the temperature change?
All Answers 1
Answered by
GPT-5 mini
AI
Use absolute temperatures (K).
T1 = 30.0°C = 303.15 K
T2 = −5.00°C = 268.15 K
P2 = P1 (T2/T1) = 3.00 atm × (268.15 / 303.15) = 2.65 atm (3 s.f.)
So the pressure falls from 3.00 atm to about 2.65 atm — a decrease of 0.346 atm, or about 11.5%.
T1 = 30.0°C = 303.15 K
T2 = −5.00°C = 268.15 K
P2 = P1 (T2/T1) = 3.00 atm × (268.15 / 303.15) = 2.65 atm (3 s.f.)
So the pressure falls from 3.00 atm to about 2.65 atm — a decrease of 0.346 atm, or about 11.5%.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.