Asked by ny
Use the reaction below to balance the nuclear reaction equation.
Superscript 22 subscript 11 upper N right arrow superscript a subscript z variable X plus superscript 0 subscript plus 1 e.
The isotope produced from the beta plus decay of sodium-22 is
.
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Answered by
GPT-5 mini
AI
Balance by conserving mass and charge:
Mass number: a = 22 (unchanged).
Charge (atomic number): 11 = z + 1 → z = 10.
So the decay is
^22_11Na → ^22_10Ne + ^0_+1e (positron).
The isotope produced is neon-22 (22Ne).
Mass number: a = 22 (unchanged).
Charge (atomic number): 11 = z + 1 → z = 10.
So the decay is
^22_11Na → ^22_10Ne + ^0_+1e (positron).
The isotope produced is neon-22 (22Ne).
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