Question

Calculate the mass defect and the nuclear binding energy of nitrogen-14.
The mass of a proton is 1.00728 amu, and the mass of a neutron is 1.00866 amu.
The mass of a nitrogen-14 atom is 14.00307 amu.

The mass defect of nitrogen-14 is
amu. Round to the 5es001-1.jpg decimal place.
The nuclear binding energy of one nitrogen-14 atom is
x 10A J. Round to 3 significant digits.
A:

Answer 1

Z = 7, N = 7. (Electron mass used: me = 0.00054858 amu.)

Mass defect:
Δm = Z(mp + me) + N mn − matom
= 7(1.00728 + 0.00054858) + 7(1.00866) − 14.00307
= 0.11234906 amu ≈ 0.11235 amu (5 decimal places)

Binding energy:
1 u c^2 = 931.494 MeV = 1.492418056×10−10 J
BE = Δm · (1 u c^2) = 0.11234906 × 1.492418056×10−10 J
≈ 1.6767×10−11 J ≈ 1.68 × 10−11 J (3 significant digits)

Answers:
Mass defect = 0.11235 amu
Nuclear binding energy = 1.68 × 10−11 J